To get the caller class name.

Finance and Operations/AX Developer Forum
1

Hi All,

How to get the caller class name. I would like to do validation basing on the caller class name please suggest me the way to get caller class name.

Thanks in advance.

2

Hi giridhar,

you can use element.args().caller(), this will work for your condition to check the caller class

Trish!

3

Hi Trishanth,

Thanks for your reply. You asked me to use element.args().caller() right?? But, the element is used for form rite?? The above scenario works only in the case of a form and class but not between two classes i think so. In my scenario there are 2 classes where one class method is being called in another class. I want to get caller class name in the second class.Does element.args().caller() in my case. If it works can you please explain me the scenario with an example.

Thank you…

4

Don’t be surprised by answer you didn’t want, if you don’t provide enough information.

Calling class don’t know how it was called unless you provide a reference to the caller object. The most straightforward way is let the caller class to pass itself as method parameter - e.g. method(this).

Rather then working with class names, you should use is operator (in AX2012) or SysDictClass::is() in older versions. It will ensure that your code works for child classes as well and it allows you to use interfaces (e.g. _caller is SysRunable).