New line character for a text

Hi everyone,

I need to display a text composed of three parts.

I need to have a new line each time a new part begins…

How can I do that?

Thanks in advance :)

how do you differentiate the new parts in the same text…?

did you post a request for multiline already in the forum…?

if you want to use multiline then you can use it in this case… but again depends upon your requirement… how do u bifurcate the text is the key…

Anil.

Yes, I want to differentiate the parts in the same text…

For example:

EXIT(part1+part2+part3);

where part1, part2 and part3 are three texts, I want a newline after each one of them…

Is it possible?

Yes, I want to differentiate the parts in the same text…

For example:

EXIT(part1+part2+part3);

where part1, part2 and part3 are three texts, I want a newline after each one of them…

Is it possible?

yes you can use multiline before part2 and part3 use \ (back slash so that they move on to the next line in the same control)

I don’t understand you very well…

Can you explain more?

For example, with EXIT(part1+part2+part3);

how should I use the \ ?

Be half of Anil,he is suggesting like Exit(Part1+’’+Part2+’’+Part3);

It doesn’t work…

It just displays the \ before the text…

That should be kept in the textbos with multiline property yes for that textbox…

Exit can not give you new lines…!

Anil.

I am not working with a textbox…

K then where are u trying to display the three parts…?

please explain your situation clearly… that will allow us to give proper solution…

Anil.

Where you are desplaying the text(while pritning or as a value of feild)…?Explain the scenario more ?

suggestion of \ works only for the message.

I am using the three texts in the body of a mail…I am using codeunit 397 to create the mail…

Try this

//char1 and char2 are both variables of datatype “char”

char1 := 13;
char2 := 10;

Exit(Part1+format(char1)+Format(Char2)+Part2+format(char1)+Format(Char2)+Part3);

Thank you for you effort…

I tried it…It inserted a space between texts, not a new line…

Sorry that is was 9 not 10.

Try this again

char1 := 13;
char2 := 9;

Exit(Part1+format(char1)+Format(Char2)+Part2+format(char1)+Format(Char2)+Part3);

Sorry, it didn’t work…

Sorry it didn’t work …

Sorry it didn’t work…

Sorry it didn’t work…