i have postableform , lostable form when i click the postable form new button i want to display the lostable form
which logic i have to write under datasource of postable create method and what code i have to write lostable form init method
i have postableform , lostable form when i click the postable form new button i want to display the lostable form
which logic i have to write under datasource of postable create method and what code i have to write lostable form init method
The similar cases can be found for sales and purchase orders. When you click on new it will open a new form.
See \Forms\SalesTable\Data Sources\SalesTable\Methods\create method in that salesTableForm.create() call will open the another form.
You can use menufunction. In POSTable create, can write like this
Args args = new Args();
;
args.record(POSTable);
new MenuFunction(MenuItemDisplayStr(LOSTable),MenuItemType::Display).run(Args);
and in init method of the LOSTable you can get the buffer of POSTable.
For more.
thank u … to reply my problem i will try