Hi All,
I want to show selected record in a new form.
Share your Ideas…
Hi All,
I want to show selected record in a new form.
Share your Ideas…
Hi sai bobby,
First conform u r selecting a record in form right, u want to show that record in another form , If another form is already created , Then in selected record form create a Itembuttonmenu Give Prop : MenuItemType -Display & MenuItemName- XXXX. Before that create a menuitem-Display - Your newform. After that when u select a record and click on button record will open new form…Hope it will work.
take a button->clicked()
void clicked()
{
Args _args;
FormRun _formRun;
;
super();
_args = new Args();
_args.name(formstr(“Your New”));
_formRun = ClassFactory.formRunClass(_args);
_args.record(“Your current Form Table”);
_formRun.init();
_formRun.run();
_formRun.wait();
}
in new form init()
Table tb;
;
tb = element.args().record();
DS->ExecuteQuery()
while select NewFormTable where NewFormTable.field == tb.field
{
}
this will work for you
Best wishes.
Hi,
try this link You will find a post, this is for report same way u can do for Forms.
http://axhelper.blogspot.com/2010/10/pass-parameter-to-dynamicsax-report.html
Hi Suni,
Thank you