check Menitem from a report name

Dynamics 365 for Finance and Operations/AX Developer Forum
1

Hi,

I have a report name and want to write a code to find whether a menuitem (in output) exists for that particular report or not.

The name of the report might not be the same in the menuitem/output node.

Please help me out.

Thanks and Regards,

Vikas Mehta.

2

this may help you

static void findingMenuItem(Args _args)

{

Dictionary dict = new Dictionary();

TreeNode menuItemsNode = TreeNode::findNode(@’\Menu Items\Output’);

TreeNodeIterator iterator = menuItemsNode.AOTiterator();

TreeNode menuItemNode = iterator.next();

SysDictMenu sysdictmenu;

;

while (menuItemNode)

{

sysdictmenu= SysDictMenu::newMenuItem(menuItemNode.treeNodeName(), MenuItemType::Output);

if(sysdictmenu.object().AOTname() == “AgentInvoice”)

{

print strfmt(“The Menu Item exists with Name → %1”,sysdictmenu.name());

break;

}

menuItemNode = iterator.next();

}

pause;

}

3

Hi,

Use function – Global::reportName2Pname(reportName)…

Naresh kolli

4

thanks Kranti,

your code worked for me.

I tried this:

while (enum.moveNext())
{
menuItem = enum.current();

if(menuItem.isMenuItem() && menuItem.isVisible() )
{

if(menuItem.menuItem().objectType()==str2enum(UtilElementType,“Report”) && menuItem.menuItem().object()==reportnamestr)
{
info(menuItem.label());
}
}

}

5

thanks Naresh

6

Small change in the above code.

static void findingMenuItem(Args _args)

{

Dictionary dict = new Dictionary();

TreeNode menuItemsNode = TreeNode::findNode(@’\Menu Items\Output’);

TreeNodeIterator iterator = menuItemsNode.AOTiterator();

TreeNode menuItemNode = iterator.next();

SysDictMenu sysdictmenu;

;

while(menuItemNode)

{

sysdictmenu = SysDictMenu::newMenuItem(menuItemNode.treeNodeName(), MenuItemType::Output);

if(sysdictmenu.menuItem().object() == “ReportName”)///here is the change

{

info(strfmt(“The Menu Item exists with Name → %1”,sysdictmenu.name()));

}

menuItemNode = iterator.next();

}

pause;

}

7

thanks,

that change was understood.