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00:00 - 00:59 | this question is if Sigma are very from zero till in our + 2 upon 1 + 1 into NCR is equal to 2 to the power 8 - 1 / 6 then n is header options are 846 aur 5 no the given expression the left inside can be written as Sigma are varies from zero R + 1 + 1 upon 1 + 1 into NCR this this is equal to Sigma aur varies from zero telin in CR plus Sigma are varies from 0 to 1 upon 1 + 1 into NCR formula that |

01:00 - 01:59 | in CR into n + 1 upon 1 + 1 is equal to N + 1 c h + 1 so using this result we can get this is equal to Sigma are varies from 0 till in in CR plus Sigma han varies from 0 to 1 upon 1 + 1 into 1 + 1 CR plus 1 no sense in plus one will be constant term for this can be taken out of the Sigma so we'll get Sigma are request 20 tailor in NCR + 1 upon 3 + 1 into Sigma are very from 0 to N + 1 |

02:00 - 02:59 | CR plus 12 for this will use Binomial expansion so we know that 1 + x to the power in is equal to in C 0 + NC 1 into X + nc2 into x square and so on 10 in cm into extra power and no hair if we put x equals to 1 we get to the power in equals to Sigma are very from zero tailor in NCR and if you find out oneplus x to the power n + 1 forget this is equal to 1 + 10 + n + 1 C 1 into X + 1 + 1 c 2 into x square and Sone last will get in plus one see in |

03:00 - 03:59 | + 1 into x to the power n + 1 foot X equals to 1 year will get 2 to the power n + 1 equal to 1 + Sigma are varies from zero till in n + 1 CR Plus 14 get the value of both the Sigma from here therefore we can write that 2 to the power in class 2 to the power n + 1 minus one upon n + 1 is equal to 2 to the power 8 minus one upon 6 As given in the question so for the following this we get 2 to the power n n 2n + 3 minus one upon n + 1 is equal to know this can be modified and written as to the power |

04:00 - 04:59 | 5 into we get to the power 3 minus 1 divided by 6 text a right to the power n 2n + 2 + 3 - 1 / n + 1 and this is equal to 2 ^ size in 28 which can be written as 5 + 3 minus one upon 610 S5 plus one know if we compare both the right inside left inside and comparing with get that the value of n is equal to 5 therefore any quiz 25 is a required answer no checking options we see that option d is the correct answer thank you |